factorize each of the followings
(use cross method)
1. x² - 4xy - 32y²
2. 6a² - 23ab + 7b²
3. 70a² - 2ab - 12b²
F.2 Maths
2007-05-12 3:33 am
回答 (5)
2007-05-12 4:19 am
✔ 最佳答案
1.x²-4xy-32y²x＼／-8y
x／＼+4y
-8xy +4xy=-4xy
so,x²-4xy-32y²=(x-8y)(x+4y)
2.6a²-23ab+7b²
2a＼／-7b
3a／＼-b
-21ab -2ab=-23ab
so,6a²-23ab+7b²=(2a-7b)(3a-b)
3.70a²-2ab-12b²=
7a ＼／-3b
10a／＼+4b
-30ab +28ab=-2ab
so,70a²-2ab-12b²=(7a-3b)(10a+4b)=2(7a-3b)(5a+2b)
參考: 自己
2007-05-12 3:56 am
1. x² - 4xy - 32y²=(x+4y)(x-8y)
2. 6a² - 23ab + 7b²=(3a-b)(2a+7b)
3. 70a² - 2ab - 12b²=2(7a+3b)(5a-2b)
2. 6a² - 23ab + 7b²=(3a-b)(2a+7b)
3. 70a² - 2ab - 12b²=2(7a+3b)(5a-2b)
2007-05-12 3:52 am
1. (x-8y)(x+4y)
2. (2a-7b)(3a-b)
3. wait
2. (2a-7b)(3a-b)
3. wait
2007-05-12 3:49 am
1. x² - 4xy - 32y² = (x-8y)(x+4y)
2. 6a² - 23ab + 7b² =(2a-7b)(3a-b)
3. 70a² - 2ab - 12b² = 2(35a²-ab-6b² )
= 2(7a-3b)(5a+2b)
2. 6a² - 23ab + 7b² =(2a-7b)(3a-b)
3. 70a² - 2ab - 12b² = 2(35a²-ab-6b² )
= 2(7a-3b)(5a+2b)
參考: ME~~~~~
2007-05-12 3:45 am
1. x² - 4xy - 32y²
=(x+4y)(x-8y)
2. 6a² - 23ab + 7b²
=(3a-b)(2a+7b)
3. 70a² - 2ab - 12b²
=2(35a²-ab-6b²)
=2(7a+3b)(5a-2b)
=(x+4y)(x-8y)
2. 6a² - 23ab + 7b²
=(3a-b)(2a+7b)
3. 70a² - 2ab - 12b²
=2(35a²-ab-6b²)
=2(7a+3b)(5a-2b)
收錄日期: 2021-04-12 19:53:57
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