How to calculate this?
個S係代表integration個符號.
1
S((-12e^(3x))/((5-4e^(3x))^(4/3))) dx
0
Integration problem
2007-05-11 7:51 am
回答 (2)
2007-05-12 5:33 am
✔ 最佳答案
Let t = 5 - 4e^(3x)dt = -12e^(3x) dx
When x = 0, t = 1
When x = 1, t = 5 - 4e^3
Therefore,
1
S [ -12e^(3x) / ( (5 - 4e^(3x)) ^(4/3) ) ] dx
0
5 - 4e^3
= S [ dt / t^(4/3) ]
1
= [ -3t(^-1/3) ] upper = 5 - 4e(^3), lower = 1
= 3 - 3 (5 - 4e(^3) ) (^-1/3)
參考: Myself
2007-05-11 11:49 am
let t=5-4e^(3x)
dt=-12e^(3x)dx
So
1
S((-12e^(3x))/((5-4e^(3x))^(4/3))) dx
0
1
=S 1/t^(4/3) dt
0
1
=S t^(-4/3) dt
0
=-3t^(-1/3) |1,0
但0^(-1/3) 是無限大
不知你是否打錯了問題?
dt=-12e^(3x)dx
So
1
S((-12e^(3x))/((5-4e^(3x))^(4/3))) dx
0
1
=S 1/t^(4/3) dt
0
1
=S t^(-4/3) dt
0
=-3t^(-1/3) |1,0
但0^(-1/3) 是無限大
不知你是否打錯了問題?
收錄日期: 2021-04-11 17:23:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070510000051KK05545