Maths!!!!!!!(數學高手請進)(10點)

用戶96296

2007-05-08 1:17 am

請把下列題目列明題目算下答案!!!!
PS.(2)=２次方

1) (3a-b)+(2a+2b)-(4a-3b)

2) (-6x+9)-(2x-11)-(13+5x)

3) (8a+5b-2c)+(7c+4b-6a)

4) (9x-7y+2z)+(9y-2z+3x)

5) (9-a+a(2) )+(-2+4a-6a(2) )

6) (7-2a(2) ) +(a(2)-7a+8)

7) (6p+8q-5r)-(4q-3p+2r)

8) (7a-8b-c)-(9c-6a+4b)

9) (-c+5c(2)-6)-(8+2c(2)-3c)

10) (-6-b+11b(2) )-b(2)+7-6b)

Thank You very much!!!!! :-)

回答 (1)

Kawai

2007-05-08 1:33 am

✔ 最佳答案

1) (3a-b)+(2a+2b)-(4a-3b)
3a-b+2a+2b-4a+3b
=a+4b
2) (-6x+9)-(2x-11)-(13+5x)
-6x+9-2x+11-13-5x
=-13x+7
3) (8a+5b-2c)+(7c+4b-6a)
8a+5b-2c+7c+4b-6a
=2a+9b+5c
4) (9x-7y+2z)+(9y-2z+3x)
9x-7y+2z+9y-2z+3x
=12x+2y
5) (9-a+a(2) )+(-2+4a-6a(2) )
9-a+a(2)-2+4a-6a(2)
=7+3a-5a(2)
6) (7-2a(2) ) +(a(2)-7a+8)
7-2a(2) +a(2)-7a+8
=15-a(2)-7a
7) (6p+8q-5r)-(4q-3p+2r)
6p+8q-5r-4q+3p-2r
=9p+4q-7r
8) (7a-8b-c)-(9c-6a+4b)
7a-8b-c-9c+6a-4b
=13a-12b-10c
9) (-c+5c(2)-6)-(8+2c(2)-3c)
-c+5c(2)-6-8-2c(2)+3c
=2c3c(2)-14
10) (-6-b+11b(2) )-(b(2)+7-6b)
-6-b+11b(2)-b(2)-7+6b
=-13+5b+10b(2)

我估應該都！
希望幫到你La！

參考: 自己

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