How to rewrite this
ln(y) − ln(y − 1) = ln(x2 + 6) − ln x
into this
y(x) = (x^2 +6) / (x^2+6-x)
pure maths
2007-05-07 2:22 am
回答 (1)
2007-05-07 11:24 am
✔ 最佳答案
ln(y) − ln(y − 1) = ln(x2 + 6) − ln xln[y/(y − 1)] = ln[(x^2 + 6)/x] [ln(a/b)=lna-lnb]
y/(y − 1)=(x^2 + 6)/x [ln is an increasing function]
xy=(y-1)(x^2+6)
xy=y(x^2+6)-(x^2+6)
y(x^2-x+6)=(x^2+6)
y(x) = (x^2 +6) / (x^2+6-x)
收錄日期: 2021-04-11 17:26:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070506000051KK04115