25.0cm3 of a 1M solution of an acid requires 37.5cm3 of 2M sodium hydroxide solution
for neutralization.what is the basicity of the acid??
f4 chem please help me~~
2007-05-06 8:36 pm
回答 (2)
2007-05-06 8:50 pm
✔ 最佳答案
HnA + nNaOH --> NanA + nH2Omole of acid: 0.025dm^3*1M=0.025mol
mole of sodium hydroxide: 0.0375dm^3*2M=0.075mol
mole ratio of acid to NaOH=1:3
n=3 <=> tribasic acid
2007-05-08 12:40:58 補充：
explanation:
eg. H2SO4, = n=2, dibasic, 1 mol H2SO4 ionises to give 2mol H+
HNO3, = n=1, monobasic, 1 mol HNO3 ionises to give 1 mol H+
HnA, n-basic, 1mol HnA ionises to give n mol H+
A- is the anion part of the acid
參考: myself
2007-05-07 11:05 pm
HnX + nNaOH → NanX + nH2O
no. of mole of HnX used = 1*(25.0/1000) = 0.025
no. of mole of NaOH used = 2*(37.5/1000) = 0.075
from the equation, mole ratio of HnX : NaOH = 1 : n
0.025/0.075 = 1/n
n = 3
so the acid is a tribasic acid
no. of mole of HnX used = 1*(25.0/1000) = 0.025
no. of mole of NaOH used = 2*(37.5/1000) = 0.075
from the equation, mole ratio of HnX : NaOH = 1 : n
0.025/0.075 = 1/n
n = 3
so the acid is a tribasic acid
參考: me*
收錄日期: 2021-04-12 20:24:57
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