會考數學題

a) Assuming that the marks of each paper distribute normally,
We consider Z = (X - A)/S where X is the score, A is the Arithmetric Mean, S is the standard deviation
The larger the Z, the better performance.
Z1 = (54-46.1)/15.2 = 0.519736842...
Z2 = (66-60.3)/11.6 = 0.49137931...
Therefore, the performance of paper 1 is better.

b) Paper 1
Arithmetric Mean : 46.1 + 4 = 50.1
Median = 46 + 4 = 50
Standard deviation = 15.2 + 0 = 15.2
Range : 91 + 0 = 91

You may visit
http://zh.wikipedia.org/w/index.php?title=%E6%AD%A3%E6%80%81%E5%88%86%E5%B8%83&variant=zh-hk
but I think they may be too difficult