1. The height of John is 160cm, correct to the nearest 1cm.
For this data, find the maximum, relative and % error.
2. The tempature of a container is 25 degree Celcius. If the % error of the measured
tempature is 10%, find the lower limit and the upper limit of the actual tempature of
the container
3. Ax - 8 ≡ 4(3x+B)
4. 4(x+5) - 2(3x+10) ≡ Ax + B
Maths Question (20 marks)
2007-05-02 3:23 am
回答 (1)
2007-05-02 3:28 am
✔ 最佳答案
1. Maximum error=1 * 1/2
=0.5cm
Relative error
=0.5 / 160
=1/320
% error
=0.5 / 160 * 100%
=0.3125%
2. The lower limit of the actual tempature
=25 * (1-10%)
=25 * 90%
=22.5degree
The upper limit of the actual tempature
=25 * (1+10%)
=25 * 110%
=27.5degree
3. Ax - 8 ≡ 4(3x+B)
LHS=Ax-8
RHS=4(3x+B)
=12x+4B
A=12
B=-2
4. 4(x+5) - 2(3x+10) ≡ Ax + B
LHS=4(x+5)-2(3x+10)
4x+20-6x-20
=-2x
A=-2
B=0
參考: 自己
收錄日期: 2021-04-25 19:52:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070501000051KK04467