3. An oxide of element X has the formula X2O3. 10.2 g of this oxide contains
5.4 g of X. What is the relative atomic mass of X ?
(Relative atomic mass : O = 16.0)
A. 12.0
B. 18.0
C. 27.0
D. 36.0
Also, How to calculate it?
F.5 Chem (MC) ( urgent)
2007-04-30 6:50 am
回答 (1)
2007-04-30 7:07 am
✔ 最佳答案
Ans:cO有4.8g
X2O3 氧化物有：(4.8/3)/16 mol
10.2/(3*16+2*X)=0.1
then...x=27
收錄日期: 2021-04-23 16:59:01
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