Gases X and Y react to give a gaseous product Z. The reaction can be
represented by the equation :
X(g) + 3Y(g) → 2Z(g)
In an experiment, 40 cm3 of X and 60 cm3 of Y are mixed and are allowed
to react in a closed vessel. What is the volume of the resultant gaseous
mixture ?
(All volumes are measured at room temperature and pressure.)
A. 40 cm3
B. 60 cm3
C. 80 cm3
D. 100 cm3
How to calculate it?
F.5 Chem (MC) (Quick)
2007-04-30 6:09 am
回答 (2)
2007-04-30 6:14 am
✔ 最佳答案
In terms of moles:X: 40/24 = 1.6
Y: 60/24 = 2.5 (therefore is the limiting reagent)
20 cm3 of x will react with 60 cm3 of y to give 40 cm3 of z
20 cm3 of remaining x + 40 cm3 of z = 60 cm3
2007-04-30 6:18 am
The stoichiometric ratio of the equation is X:Y:Z = 1:3:2
1 volume of X will react with 3 volume of Y --> produce 2 vol of Z
In this situation, the limiting reagent is Y -- used up 60 cm3 and will consume 20cm3 of X, produce 2x20cm3=40cm3 of Z
The total volume after reaction = Vol sum of ( X+Y+Z)
= ((40-20) -X + (60-60) -Y + (40) -Z ) cm3
= 60cm3
1 volume of X will react with 3 volume of Y --> produce 2 vol of Z
In this situation, the limiting reagent is Y -- used up 60 cm3 and will consume 20cm3 of X, produce 2x20cm3=40cm3 of Z
The total volume after reaction = Vol sum of ( X+Y+Z)
= ((40-20) -X + (60-60) -Y + (40) -Z ) cm3
= 60cm3
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