我想問一條question:
n=唔知幾多次
n(C6H12O6)=[C6H10O5]+?
Thx!
disaccharide ~
2007-04-28 7:10 pm
回答 (2)
2007-04-30 8:02 pm
✔ 最佳答案
disaccharide,di = two, saccar = sugar,
=> disaccharide = two sugar,
(C6H12O6) is monosaccharide,(mono = one)
(C6H12O6) + (C6H12O6) ---> (C12H22O11) + H2O
two (C6H12O6) react and one (C12H22O11) is formed.
(C12H22O11) is a disaccharide.
n X (C6H12O6) ---> (C6H10O5)n + n X H2O,
(C6H10O5)n is a polysaccharide. (poly = many)
2007-04-29 6:42 am
n(C12H22O11)+ H2O= 2n(C6H12O6)
收錄日期: 2021-04-12 23:59:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070428000051KK01238