A student adds 0.2 kg of ice at 0C into 0.4kg of hot tea at 80C.
What is the final temperature of the mixture ?
(The specific heat capacity of tea is 4000 J kg-1 C-1 )
thank you
F3 physics question in book
2007-04-26 6:01 am
回答 (1)
2007-04-26 8:06 am
✔ 最佳答案
Final temperature = ToC.Heat gained for 0oC ice to 0oC water then ToC water
= mL + mcΔT
= (0.2)(334000) + (0.2)(4200)(T - 0)
= 66800 + 840T
Heat lost for 80oC of tea to ToC of tea
= mcΔT
= (0.4)(4000)(80 - T)
= 128000 - 1600T
Since net heat change = 0,
66800 + 840T = 128000 - 1600T
2440T = 61200
Final temperature T = 25.1oC
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