超難數學題
回答 (2)
2007-04-25 6:17 am
(1111+1234)/2004=2345/2004=345
2007-04-24 22:18:46 補充：
no345is341Sorry!
2007-04-24 22:18:46 補充：
no345is341Sorry!
參考: thank
2007-04-25 5:12 am
Very easy.
p mod 2004 = 1111
q mod 2004 = 1234
(p+q) mod 2004 = (1111+1234) mod 2004 = 2345 mod 2004 = (2345-2004) mod 2004
= 341 mod 2004
So 餘數= 341.
p mod 2004 = 1111
q mod 2004 = 1234
(p+q) mod 2004 = (1111+1234) mod 2004 = 2345 mod 2004 = (2345-2004) mod 2004
= 341 mod 2004
So 餘數= 341.
收錄日期: 2021-04-12 23:55:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070424000051KK04586