✔ 最佳答案
First differentiate both sides w.r.t x
LHS = 1/(1+(x^2y)^2) * d(x^2y)dx
= 1/(1+(x^2y)^2) * (2xy + x^2*dy/dx)
RHS = d(xy^2)/dx = y^2 + 2xy*dy/dx
Equating both sides,
1/(1+(x^2y)^2) * (2xy + x^2*dy/dx) = y^2 + 2xy*dy/dx
2xy/(1+(x^2y)^2) + [x^2/(1+(x^2y)^2)]*dy/dx) = y^2 + 2xy*dy/dx
2xy/(1+(x^2y)^2)-y^2 = [2xy-x^2/(1+(x^2y)^2)]*dy/dx
(2xy-y^2-x^4y^4)/(1+(x^2y)^2) = (2xy+2x^5y^3-x^2)/(1+(x^2y)^2)*dy/dx
dy/dx = (2xy-y^2-x^4y^4)/(2xy+2x^5y^3-x^2)