An object passing a mark with a velocity y ms-1 eastward is subjected to a constant acceleration of x ms-2 in a westward direction. How long, in seconds, will it take to return to the same mark?
A). y^2 / x
B). y^2 / 2x
C). y /x
D). 2y / x
The ans. is (D), how to find it is (D)??
mechanics of physics
2007-04-24 9:46 pm
回答 (2)
2007-04-24 9:56 pm
✔ 最佳答案
Y/x is the distance goIt needs to *2 because it needs to return.
2007-04-24 10:58 pm
s=ut+1/2at^2
0=yt+1/2(-x)t^2
t=(2y)/x
0=yt+1/2(-x)t^2
t=(2y)/x
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