Very Urgent

Let the position of the starting point be O.
Let the positions of Nancy and Kenny be N and K, respectively.

(You should notice that the angle between S58E and S32W is 90°)

Since ∠NOK = 90°, then
NK²
= ON² + OK²
= (8*3)² + (6*3)²
= 900

NK = 30

Their distance apart after 3 hours are 30km.

tan ∠ONK = (6*3) / (8*3)
∠ONK = 37°

Since 37° > 32°, then 90°- ( 37° - 32°) = 85°
the compass bearing of Nancy from Kenny is S85°W