1) In the game of Poker, 5 cards are dealt to each player. What is the probability of the first person being dealt the following hands being if all 5 cards are given to each player in succession?
a) three of a kind(3 of one value and 2 cards that are different)
b) a flush (all 5 cards are the from the same suit)
Probability Math problem!
2007-04-20 6:54 pm
回答 (2)
2007-04-20 7:27 pm
✔ 最佳答案
(a) (if the last two cards have no restriction of being of same suit)
(13C1 * 4C3 * 12C1 * 4C1 * 11C1 * 4C1) / 52C5 = 0.04226
otherwises, if they have to be different in number and different in suit
(13C1 * 4C3 * 12C1 * 4C1 * 11C1 * 3C1) / 52C5 = 0.03169
(b)
(13C5 * 4C1) / 52C5 = 0.00198
參考: I am university MATH major
2007-04-21 1:30 am
Probability of three of a kind
= 13C1 * 4C3 * 12C2 * 4^2 / 52C5
= 54,912 / 2,598,960
= about 0.0211285
Probability of a flush
= 13C5 * 4 / 52C5 - 4*10 / 52C5 (need to exclude the probability of Royal Flush - 同花順及同花大順）
= 5,108 / 2,598,960
= about 0.0019654
= 13C1 * 4C3 * 12C2 * 4^2 / 52C5
= 54,912 / 2,598,960
= about 0.0211285
Probability of a flush
= 13C5 * 4 / 52C5 - 4*10 / 52C5 (need to exclude the probability of Royal Flush - 同花順及同花大順）
= 5,108 / 2,598,960
= about 0.0019654
收錄日期: 2021-04-18 21:52:03
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