A sum of $4200 is divided among Amy, Jane, and Peter. Amy gets two-thirds of Jane's, and Jane gets twice as much as Peter. How much does Jane get?
P.S.不可用方程式計算
中一英數問題
2007-04-18 12:46 am
回答 (2)
2007-04-18 1:04 am
✔ 最佳答案
Let Amy get $A, Jane get $J, Peter get $PA+J+P=4200................(1)
A=2/3 J .......................(2)
J=2P ===> P=1/2J........(3)
Put (2) and (3) into (1)
2/3J + J + 1/2J = 4200
J = $25200/13
2007-04-18 1:21 am
In this case, we can use the total number (sum=$4200) divided by the % get on each person.
So,
Jane
= $4200 / (1+1/2+2/3)
= $4200 / (13/6)
= $4200 * 6 / 13
= $25200 / 13
= $1938.46
Therefore, Jane get $1938.46.
So,
Jane
= $4200 / (1+1/2+2/3)
= $4200 / (13/6)
= $4200 * 6 / 13
= $25200 / 13
= $1938.46
Therefore, Jane get $1938.46.
收錄日期: 2021-04-12 23:52:56
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https://hk.answers.yahoo.com/question/index?qid=20070417000051KK02178