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F.2 plane geometry
2007-04-17 3:33 am
回答 (3)
2007-04-17 3:46 am
angle UPQ + angle UTS = 180° (int. angles PQ//TR)
150° + x = 180°
x = 30°
x + 3y + 2y = 180° (angle sum of triangle)
5y = 180° - 30°
y = 150° / 5
y = 30°
150° + x = 180°
x = 30°
x + 3y + 2y = 180° (angle sum of triangle)
5y = 180° - 30°
y = 150° / 5
y = 30°
2007-04-17 3:45 am
ÐPQR=90°
ÐTRQ=90°
150°+90°+90°+X=360°(Ðsum of poly.)
X=30°
X+3y+2y=180°(Ðsum of D)
30°+5y=180°
5y=150°
y=30°
2007-04-16 19:46:07 補充：
ÐPQR=90°ÐTRQ=90°150°+90°+90°+X=360°(Ðsum of poly.)X=30°X+3y+2y=180°(Ðsum of tri.)30°+5y=180°5y=150°y=30
ÐTRQ=90°
150°+90°+90°+X=360°(Ðsum of poly.)
X=30°
X+3y+2y=180°(Ðsum of D)
30°+5y=180°
5y=150°
y=30°
2007-04-16 19:46:07 補充：
ÐPQR=90°ÐTRQ=90°150°+90°+90°+X=360°(Ðsum of poly.)X=30°X+3y+2y=180°(Ðsum of tri.)30°+5y=180°5y=150°y=30
參考: 自己
收錄日期: 2021-04-13 00:16:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070416000051KK03677