中二數題=====5ab-3c-3ac+5b

2007-04-16 7:34 am
因式分解===5ab-3c-3ac+5b

回答 (3)

2007-04-16 7:38 am
✔ 最佳答案
5ab-3c-3ac+5b
=5b(a+1) - 3c(a+1)
=(5b - 3c) (a + 1)
2007-04-16 7:53 am
5ab-3c-3ac+5b
=5ab+5b-3c-3ac
=5b(a+1)-3c(1+a)
=(5b-3c)(a+1)//
2007-04-16 7:43 am
=5b(a+1)-3c(a+1)
=(5b-3c)(a+1)
參考: me


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