(log x)^2- log(3x-2)^2=2

2007-04-16 2:22 am
ANS: x=20/29 or 20/31
how to calcurate, need steps, thx~

回答 (2)

2007-04-16 2:36 am
✔ 最佳答案
2logx- 2log(3x-2)=2
logx-log(3x-2)=1
log (x/3x-2)=log10
x/(3x-2)=10
x=30x-20
-29x=20
x=20/29

2007-04-17 12:49:32 補充:
2logx- 2log(3x-2)=2logx-log(3x-2)=1log (x/3x-2)=log10x/(3x-2)=10x=30x-20-29x=-20x=20/29 另一個answer 20/31 好似唔岩...
2007-04-17 8:17 pm
唔好意思..
你個answer 係唔係錯ga..
點解代番x 都計唔到....


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