✔ 最佳答案
tan (30°+x) tan (30°-x) = 1-2cos2x
sin (30°+x) sin (30°-x)
-----.------ = 1 - 2 cos 2x
cos (30°+x) cos (30°-x)
sin (30°+x) sin (30°-x)
---------- = 1 - 2 cos 2x
cos (30°+x) cos (30°-x)
(-1/2) {cos [(30°+x)+(30°-x)] - cos [(30°+x)-(30°-x)] }
---------------------- = 1 - 2 cos 2x [註1]
(1/2) {cos [(30°+x)+(30°-x)] + cos [(30°+x)-(30°-x)]
(-1/2) (cos 60° - cos 2x)
----------- = 1 - 2 cos 2x
(1/2) (cos 60° + cos 2x)
(-1/2) (1/2 - cos 2x)
--------- = 1 - 2 cos 2x
(1/2) (1/2 + cos 2x)
- (1 - 2 cos 2x)
------- = 1 - 2 cos 2x [註2]
1 + 2cos 2x
- ( 1 - 2 cos 2x) = (1 - 2 cos 2x)(1 + 2 cos 2x)
0 = ( 1 - 2 cos 2x)(1 + 2 cos 2x + 1)
( 1 - 2 cos 2x)(1 + 2 cos 2x + 1) = 0
1 - 2 cos 2x = 0 或 2 + 2 cos 2x = 0
cos 2x = 1/2 或 cos 2x = -1
2x = 360°n±60° 或 2x = 360°n±180°
x = 180°n±30° 或 x=180°n±90° // (n=1,2,3,...)
註1 : 用積化和差公式(product-to-sum)
sin A sin B = (-1/2) [cos(A+B) - cos(A-B)]
cos A cos B = (1/2) [cos(A+B) + cos(A-B)]
註2 : 分子和分母都x4