請計下列各式
因式分解下列各式
1 2x3次方-3y+2x-3x2次方y
2 a+b+ac+bc
3 ab-3a-3b+9
4 6s+6t+sw+tw
5 2ax+3ay-5az-4x-6y+10z
6 xy+x+y+1
7 4ax+6ay-6bx-9by
8 2x3次方-3y+2x-3x2次方y
9 ux+2uv+u+2v
10 ns-s-mn+m
11 x-2-xy+2y
12 y3次方-1-y2次方+y
13 3b-3c+ab-ac
兩平方之差
1 (x+6)(x-6)
2 (3+x)(3-x)
3 (-8+y)(-8-y)
4 (4y+3)(4y-3)
5 (2x2次方+7)(2x2次方-7)
6 (2p+5p)(2p-5p)
7 (x-4)(x+4)
8 (b-12)(b+12)
9 (-k-6)(-k+6)
10 (1-x)(1+x)
回答 (2)
✔ 最佳答案
因式分解下列各式(P.S.^=次方)
1)2x^3-3y+2x-3x^2y
=2x(x^2+1)-3y(1+x^2)
=(2x-3y)(x^2+1)
2)a+b+ac+bc
=(a+b)+c(a+b)
=(1+c)(a+b)
3)ab-3a-3b+9
=b(a-3)-3(a-3)
=(b-3)(a-3)
4)6s+6t+sw+tw
=6(s+t)+w(s+t)
=(6+w)(s+t)
5)2ax+3ay-5az-4x-6y+10z
=a(2x+3y-5z)-2(2x+3y-5z)
=(a-2)(2x+3y-5z)
6)xy+x+y+1
=x(y+1)+(y+1)
=(x+1)(y+1)
7)4ax+6ay-6bx-9by
=2a(2x+3y)-3b(2x+3y)
=(2a-3b)(2x+3y)
8)2x^3-3y+2x-3x^2y
=2x(x^2+1)-3y(1+x^2)
=(2x-3y)(x^2+1)
9)ux+2xv+u+2v
=u(x+1)+2v(x+1)
=(u+2v)(x+1)
10) ns-s-mn+m
=s(n-1)-m(n-1)
=(s-m)(n-1)
11) x-2-xy+2y
=x(1-y)-2(1-y)
=(x-2)(1-y)
12)y^3-1-y^2+y
=y(y^2+1)-(y^2-1)
=(y-1)(y^2-1)
=(y-1)(y+1)(y-1)
13) 3b-3c+ab-ac
=3(b-c)+a(b-c)
=(3+a)(b-c)
兩平方之差
利用平方差公式:(a+b)(a-b)=a^2-b^2
1 (x+6)(x-6)
=x^2-36
2 (3+x)(3-x)
=9-x^2
3 (-8+y)(-8-y)
=62-x^2
4 (4y+3)(4y-3)
=16y^2-9
5 (2x^2+7)(2x^2-7)
=4x^4-49
6 (2p+5p)(2p-5p)
=4p^2-25p^2
=-21p^2
7 (x-4)(x+4)
=x^2-16
8 (b-12)(b+12)
=b^2-144
9 (-k-6)(-k+6)
=k^2-36
10 (1-x)(1+x)
=1-x^2
收錄日期: 2021-04-12 21:57:23
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