A Maths Questions 10MARKS

2007-04-15 12:10 am
1.A bus travelled 300km in 5 hours.
(a)If the average speed of the bus increases by 5 km/h, find the distance to be tralled by the bus in 1.5 hours.
(b)If the average speedof the bus reduces by 10m/s. find the distance to be travelled by the bus in 45 minutes.
2.1+1+?=100
3.1+1=?
答中其中一題就得10 MARKS
更新1:

答一題就得

回答 (3)

2007-04-15 1:39 am
✔ 最佳答案
1. Let u be the starting speed and v be the final speed

since average speed increases each hr by 5, in 5hours time, v = u+50
(v-u)/t=a(i) with constant acceleration

(u+50-u)/5=a
a=10km hr^-2
s=ut+1/2 at^2
300=5u+1/2*10*25
u=35km/hr

s=ut+1/2at^2
s=35*1.5+1/2*10*2.25
s=63.75km

(b)
10m/s=36km/hr (Nice, you are kidding me)
so in 5 hours time, v=u-360
(u-360+u)/5=a
a=-72km hr^-2

300=5u+1/2(-72)*25
u=240km/hr (What a speed)
s=240(.75)+1/2(-72)(.75)^2
=159.75km (Satisfy with it?)

2. 88
3. 2 (assume you are using 10進制 and this is a maths question)

2007-04-15 22:41:44 補充:
我好得閒回應d玩野o既題目架......
1+1+?=100
有冇人會寫88呀?
我想同你講byebye啫
2007-04-15 4:11 am
1a.(300/5+5)*1.5=97.5km
1b.(300/5-10*60*60/1000)*45/60=18km
2.?=98
3.?=2
2007-04-15 12:23 am
1.((300/5)+5)*1.5=97.5
Therefore the ans of a is 97.5km
((300/5)-10)*0.75=37.5
Thus the ans of b is 37.5km
2:98
3:2
I'm not sure about the ans is correct or not


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