Maths easy question 4題 10分

1)since50￠coins and $2 coins in the ratio of 10:7,21 $2 coins
the ratio is 30:21(30=21/7*10)
the total value=30(50)+2(21)=$1542
2)30km/h=3000m /3600s=0.833m/s
1:120(not sure)
3)let x be the day fanny should work:
(2070/5)x=5060
x=12.2

1.
Let x be the number of 50￠coins
x:21 = 10:7
x = 30

Total value of all coins in the pocket
= 30*0.5 + 21*2
= $57

2.
30km/h : 10 m/s
=30,000m/h : 10m/s
= 30,000/3600 m /s : 10m/s
= 5:6

3.
Hourly wages of Fanny
= $2,070 / 5
= $46 per hour
No. of days Fanny work to earn $5,060
= $5,060 / $46 / 9
= 12.2 days
Fanny at least work 13 days to earn $5,060
If including the weekday, Fanny need 2 weeks and 3 days to earn (i.e. 17 days)
4a.
tones of food each adult consume daily
= k/ (200*25)
= k/5000 tonnes
4c.
tones of food each child consume daily
= k/20,000 tonnes
Each day with 500 adults and 500 child, the daily consumption of food is
=(k/5000 + k/20000) * 500
= k/8 tonnes
Number of days the food can supply last
= k / (k/8)
= 8 days