把公式m-n=pw-qw的主項變換為w
點轉?
我轉到w-w.........
教教我=.="
數學問題!!!
2007-04-14 9:25 pm
回答 (9)
2007-04-14 9:28 pm
✔ 最佳答案
m-n=pw-qwm-n=w(p-q)
w=(m-n)/(p-q)
2007-04-16 20:48:51 補充：
1. 你漏左個x?如果唔係中間果項冇可能有x16x^2 24xy 9y^2=(4x)^2 2*12xy (3y)^2=(4x 3y)^22.121x^2-22xy y^2=(11x)^2-2*11xy y^2=(11x-y)^2
2007-04-16 20:49:27 補充：
d加號都係出唔到../ \
參考: 自己
2007-04-16 12:57 am
m-n=pw - qw
m - n = w(p - q) (factorize pw - qw)
w = (m - n)/(p - q)
factorize:
(a) 16x^2+24xy+9y^2
i think it should be 16x^2....
16x^2 + 24xy + 9y^2
=(4x)^2+2(3y)(4x)+(3y)^2
=(4x + 3y)^2
(b) 121x^2-22xy+y^2
=(11x)^2-2(11x)(y)+y^2
=(11x - y)^2
m - n = w(p - q) (factorize pw - qw)
w = (m - n)/(p - q)
factorize:
(a) 16x^2+24xy+9y^2
i think it should be 16x^2....
16x^2 + 24xy + 9y^2
=(4x)^2+2(3y)(4x)+(3y)^2
=(4x + 3y)^2
(b) 121x^2-22xy+y^2
=(11x)^2-2(11x)(y)+y^2
=(11x - y)^2
2007-04-14 9:34 pm
m-n=pw-qw
將w作為主項:
m - n = pw - qw
m - n = *w( p -q ) *(抽取共同擁有的因子"w")
(m - n)/(p - q )* = w *(w與(p-q)是乘數關係,可將乘數(p-q)轉換成左方作為除數)
∴ w = ( m - n ) / (p - q)
將w作為主項:
m - n = pw - qw
m - n = *w( p -q ) *(抽取共同擁有的因子"w")
(m - n)/(p - q )* = w *(w與(p-q)是乘數關係,可將乘數(p-q)轉換成左方作為除數)
∴ w = ( m - n ) / (p - q)
參考: 自己
2007-04-14 9:32 pm
m-n=pw-qw
m-n=w(p-q)
m-n
------ = w
p-q
m-n
w=-------
p-q
=================================
w= m-n
--------
p-q
w(p-q) = m-n
m-n= wp-wq
so, w= m-n
--------
p-q
2007-04-14 13:32:49 補充：
m-n--------= (m-n)/(p-q)p-q
m-n=w(p-q)
m-n
------ = w
p-q
m-n
w=-------
p-q
=================================
w= m-n
--------
p-q
w(p-q) = m-n
m-n= wp-wq
so, w= m-n
--------
p-q
2007-04-14 13:32:49 補充：
m-n--------= (m-n)/(p-q)p-q
2007-04-14 9:28 pm
m-n=pw-qw
m-n=w(p-q)
w=m-n/p-q
m-n=w(p-q)
w=m-n/p-q
2007-04-14 9:28 pm
m-n=pw-qw
m-n=w(p-q)
(m-n)/(p-q)=w
w=(m-n)/(p-q)
m-n=w(p-q)
(m-n)/(p-q)=w
w=(m-n)/(p-q)
收錄日期: 2021-04-12 22:22:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070414000051KK02148