B's age is half of A's,and two-third of C's. Their combined age is 63 years old. What is their age?
Show steps and use algebra ....
Thx``
F.1 Maths
2007-04-13 11:12 pm
回答 (2)
2007-04-13 11:34 pm
A:B:C=2 : 1: 1.5
=2x2 : 1x2 : 1.5x2
=4 : 2 : 3
C的age
=63/(4+2+3)x3
=21
B的age
=63/(4+2+3)x2
=14
A的age
=63/(4+2+3)x4
=28
=2x2 : 1x2 : 1.5x2
=4 : 2 : 3
C的age
=63/(4+2+3)x3
=21
B的age
=63/(4+2+3)x2
=14
A的age
=63/(4+2+3)x4
=28
參考: 一定對
2007-04-13 11:18 pm
Let the age of C is X
B = 2/3 X
A = 2 * 2/3 X = 4/3X
solution :
X + 2/3X + 4/3X = 63
X + 6/3X = 63
3X = 63
X = 21
So, age of A = 4/3 * 21 = 28 ; B = 2/3X = 14 and C = 21
B = 2/3 X
A = 2 * 2/3 X = 4/3X
solution :
X + 2/3X + 4/3X = 63
X + 6/3X = 63
3X = 63
X = 21
So, age of A = 4/3 * 21 = 28 ; B = 2/3X = 14 and C = 21
參考: myself
收錄日期: 2021-04-12 21:28:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070413000051KK02998