maths question

let y be the age of his son
let z be the age of his daughter
2y+1=x......(1)
3z+2=x......(2)
x+y+z=98-x......(3)
Form(1)&(2),
2y+1=3z+2
2y-1=3z
z=(2y-1)/3
Sub , x=2y+1,z=(2y-1)/3 into (3)
(2y+1)+(2y-1)/3+y=98-(2y+1)
6y+3+2y-1+3y=294-6y-3
17y=289
y=17
sub y=17 into (1)
x=2(17)+1
x=35
sub x=35 into(2),
3z+2=35
3z=33
z=11
Therefore, the age of Jacky is 35 his daughter is 17 years old and his son is 11 years old

Solutions: "Jacky's age + his son's age + his daughter's age = 98-x
∴educe this formula: x + (x/2+1) + (x/3+2) = 98-x"


x + (x/2+1) + (x/3+2) = 98 - x
x + (x+2)/2 + (x+6)/3 = 98 - x
(x+2)/2 + (x+6)/3 = 98 - x - x
[3(x+2) + 2(x+6)]/6 = 98 -2x
(3x+6) + (2x+12) = (98-2x)6
3x + 6 + 2x + 12 = 588 - 12x
5x +18 = 588 - 12x
17x = 588 - 18
x = 570/17
x = 33.5

∴Jacky is 33.5 years old,
his son is (33.5)/2+1 = 17.75 (17.8years old)
his daughter is (33.5)/3+2 = 13.16 (13.2years old)

x + (x-1)/2 + (x-2)/3 = 98 - x
6x + 3x - 3 + 2x - 4 = 588 - 6x
11x + 6x = 588 + 7
17x = 595
x = 35