i.e. 1 x 2 x 3 x 4 x 5 x 6 x ... x 26
= 223 x 310 x 56 x 73 x 112 x 132 x 17 x 19 x 23
we have the factor of 26 x 56
so there are 6 '0's at the end
2007-04-11 12:45:24 補充:
for the purpose of this question, we do not need to consider other prime factors (i.e. 3, 7, 11, 13, 17, 19, 23)i just try to give a more complete picture of the story behind
2007-04-11 14:09:14 補充:
for the answer about 1-10, 11-20, 21-26....what if the product of a number from 1-10 and another number from 21-26 contribute to a multiple of 10?