數學題...趕

2007-04-08 7:59 pm

一艘輪船以24km/h 的速率行2又4份1小時後, 再以18km/h的速率行1又2份1小時. 輪船行的總距離是多少?

回答 (7)

2007-04-08 8:18 pm

✔ 最佳答案

24x2又4份1+18x1又2份1
=54+18x1又2份1
=54+27
=81(公里)
所以輪船行的總距離是81公里

驗算:
24x2又4份1
=24x2+24/4
=48+6
=54

18x1又2份1
=18x1+18/2
=18+9
=27

54+27
=81(公里)

👍 0 👎 0

2007-04-09 6:47 pm

輪船行的總距離是81km

👍 0 👎 0

2007-04-08 10:27 pm

距離=速率*時間
d=24*(9/4)+18*(3/2)
d=81km

參考: by myself

👍 0 👎 0

2007-04-08 8:37 pm

Answer is 81km

👍 0 👎 0

2007-04-08 8:36 pm

24km/hr X 2.25hr + 18km/hr X 1.5hr = 81km

留意km/hr x hr 後, 單位變了km

👍 0 👎 0

2007-04-08 8:21 pm

是81km

👍 0 👎 0

2007-04-08 8:05 pm

總距離 = 24 x (2 1/4) + 18 x (1 1/2) = 81 km

p.s. (2 1/4) = 2又4份1
　　(1 1/2) = 1又2份1

參考: me =]

👍 0 👎 0