有冇人可以幫我計條數?
2007-04-07 6:50 am
A sum of $120 is divided between two sisters. The elder sister spends 1/5 of the amount received while the younger sister spends 1/6 of the amount received. If the elder sister spends $13 more than the younger sister, how much does each of them receive?
回答 (3)
2007-04-07 7:08 am
✔ 最佳答案
let $X be the amount of the elder sister received,and $(120 - X)be the amount of the younger sister received.
1/5 X = [1/6 (120 - X)] + 13
1/5 X = (20 - 1/6 X) + 13
1/5 X = 20 - 1/6 X + 13
1/5 X + 1/6 X = 20 + 13
(1/5 + 1/6) X = 33
(6/30 + 5/30) X = 33
11/30 X = 33
X = 33 x 30/11
X = 90
so, the elder sister received $90 while the younger sister received $(120 - 90) = $30
參考: mee
2007-04-07 7:14 pm
1/5 X = [1/6 (120 - X)] + 13
1/5 X = (20 - 1/6 X) + 13
1/5 X = 20 - 1/6 X + 13
1/5 X + 1/6 X = 20 + 13
(1/5 + 1/6) X = 33
(6/30 + 5/30) X = 33
11/30 X = 33
X = 33 x 30/11
X = 90
so, the elder sister received $90 while the younger sister received $(120 - 90) = $30
1/5 X = (20 - 1/6 X) + 13
1/5 X = 20 - 1/6 X + 13
1/5 X + 1/6 X = 20 + 13
(1/5 + 1/6) X = 33
(6/30 + 5/30) X = 33
11/30 X = 33
X = 33 x 30/11
X = 90
so, the elder sister received $90 while the younger sister received $(120 - 90) = $30
2007-04-07 6:59 am
Ｔｈｅ ｙｏｕｎｇｅｒ ｓｉｓｔｅｒ ｈａｓ＄５５
Ｔｈｅ ｏｌｄｅｒ ｓｉｓｔｅｒ ｈａｓ＄６５
Ｔｈｅ ｏｌｄｅｒ ｓｉｓｔｅｒ ｈａｓ＄６５
收錄日期: 2021-04-12 22:56:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070406000051KK05085