問不等式問題 - Ans.fyi 參考答案

問不等式問題

Xin

2007-04-07 1:26 am

有2條不太明,也計不了,麻煩幫幫手^^"
1. 11(x-1)-10(x-1)>-5x-(6x+5)
2. 求滿足不等式12(x+3)-10(2x-5)≧30-45x的所有負整數
請詳細步驟說明~謝

更新1:

1. 11(x-1)-10(x-1) -5x-(6x+5)

更新2:

1. 11(x-1)-10(x-1) -5x-(6x+5)

更新3:

11(x-1)-10(x-1) -5x-(6x+5) 打錯

更新4:

11(x-1)-10(x-1)大於-5x-(6x+5) 打不到符號

回答 (1)

[匿名]

2007-04-07 1:50 am

✔ 最佳答案

1, 11(x-1)-10(x-1) -5x-(6x+5)
= 11x-11-10x+10-5x-6x-5
= -10x - 6
= -1(10x + 6)

= -2(5x + 3)

Hope can help u~

2007-04-06 17:56:37 補充：
2. 12(x 3)-10(2x-5)≧30-45x12x 36-20x 50≧30-45x86-8x≧30-45x45x-8x≧30-8637x≧-56x≧-56/37

2007-04-06 17:57:27 補充：
2. 12(x 3)-10(2x-5)≧30-45x12x 36-20x 50≧30-45x86-8x≧30-45x45x-8x≧30-8637x≧-56x≧-56/37x≧1.513513513513513513513513513513...

2007-04-06 17:58:10 補充：
2. 12(x 3)-10(2x-5)≧30-45x12x 36-20x 50≧30-45x86-8x≧30-45x45x-8x≧30-8637x≧-56x≧-56/37x≧-1.513513513513513513513513513513...

參考: me

👍 0 👎 0