f(x)=x^2-4x+1 且f(a)=f(b)=0 其中a不等於b
請計算 a^2-4a+1 同 b^2-4b+1
答案係 0,0 (姐係點 唔明點解係0,0)
如果知點解 請列個步驟出黎,,,,,,plx
二次函數!!!!
2007-04-06 10:04 pm
回答 (1)
2007-04-06 10:21 pm
✔ 最佳答案
f(x) = x² - 4x +1, f(a) = f(b) = 0f(a) 即是將 x = a,
f(x) = x² - 4x +1 變成:
f(a) = a² - 4a +1 = 0
f(b) 即是將x = b,
f(x) = x² - 4x +1 變成:
f(b) = b² - 4b +1 = 0
所以,
a² - 4a +1 = 0
b² - 4b +1 = 0
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070406000051KK01836