MATHS

2007-04-06 7:40 pm
[a+(15^2-a^2)^0.5]/[a+(20^2-a^2)^0.5]=3/4,a>0

求a的值

回答 (2)

2007-04-06 8:46 pm
✔ 最佳答案
[a+(15^2-a^2)^0.5]/[a+(20^2-a^2)^0.5]=3/4

4a + 4(225 - a^2)^0.5 = 3a + 3(400-a^2)^0.5
a + 4(225-a^2)^0.5 = 3(400-a^2)^0.5
a^2 + 8a(225-a^2)^0.5 + 16(225-a^2) = 9(400-a^2)
a^2 + 8a(225-a^2)^0.5 + 3600 - 16a^2 = 3600 - 9a^2
8a(225-a^2)^0.5 = 6a^2
4(225-a^2)^0.5 = 3a
16(225-a^2) = 9a^2
3600-16a^2 = 9a2
25a^2 = 3600
a^2 = 144
a = 12 or -12 (reject)
2007-04-06 11:04 pm
<img src="http://s155.photobucket.com/albums/s287/ss3205/1.gif">
<img alt=Image src="http://s155.photobucket.com/albums/s287/ss3205/1.gif" alt="Image"/>

if can&#39;t display the above image, have a look in the following link:
http://s155.photobucket.com/albums/s287/ss3205/1.gif
參考: myself


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