求AB和EF長度之和（列式）
f.3 maths(1 question)
2007-04-06 7:32 am
回答 (3)
2007-04-06 7:56 am
✔ 最佳答案
設H在EF上和AH//BF，另AH和CD相交於G。根據中點定理，
EH = 2CG
此外， AB = GD = HF
AB + EF = AB + EH + HF
= GD + 2CG + GD
= 2GD + 2CG
= 2(CG + GD)
= 2 CD
= 2(3 cm)
= 6 cm
2007-05-04 3:19 am
Good
2007-04-06 7:38 am
根據梯形的中點定理,
(AB+EF)/2=3
所以 AB+EF=6
(AB+EF)/2=3
所以 AB+EF=6
收錄日期: 2021-04-19 20:26:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070405000051KK05174