1.某公開考試的考試費($E)可用下列公式計算:
E=250+120n , n是每名學生報考的試卷數目
a)把公式的主項變換為n
b)德華於這個公開考試中報考n份試卷, 共付考試費$1090 ,計n
中1maths
2007-04-04 6:28 am
回答 (5)
2007-04-05 7:47 pm
a) E-250=120n
E-250/120=n
n=E-250/120
b) 1090=250+120n
n=(1090-250)/120
n=7
德華於這個公開考試中報考7份試卷
E-250/120=n
n=E-250/120
b) 1090=250+120n
n=(1090-250)/120
n=7
德華於這個公開考試中報考7份試卷
2007-04-04 7:21 am
a)
E=250+120n (-250)
E-250=120n (x1/120)
n=(E-250)/120
b)
每個學生做1分卷.
n=(E-250)/120 (代入E=1090, Sub E=1090)
n=(1090-250)/120 (減數運算)
n=840/120 (除數運算)
n=4.
德華於這個公開考試中報考4份試卷
E=250+120n (-250)
E-250=120n (x1/120)
n=(E-250)/120
b)
每個學生做1分卷.
n=(E-250)/120 (代入E=1090, Sub E=1090)
n=(1090-250)/120 (減數運算)
n=840/120 (除數運算)
n=4.
德華於這個公開考試中報考4份試卷
2007-04-04 6:34 am
1.(a)
E = 250 + 120n
E - 250 = 120n
(E - 250) / 120 = n
n = (E - 250) / 120
(b)
Put E = 1090
n = (1090 - 250) / 120
n = 840 / 120
n = 7
E = 250 + 120n
E - 250 = 120n
(E - 250) / 120 = n
n = (E - 250) / 120
(b)
Put E = 1090
n = (1090 - 250) / 120
n = 840 / 120
n = 7
2007-04-04 6:34 am
a) E-250=120n
E-250/120=n
n=E-250/120
b) 1090=250+120n
n=(1090-250)/120
n=7
E-250/120=n
n=E-250/120
b) 1090=250+120n
n=(1090-250)/120
n=7
2007-04-04 6:33 am
a)把公式的主項變換為n
E = 250 + 120n
120n = E - 250
n= (E -250)/120
b)德華於這個公開考試中報考n份試卷, 共付考試費$1090 ,計n
PUT E=1090
n = (1090-250)/120
n=7
E = 250 + 120n
120n = E - 250
n= (E -250)/120
b)德華於這個公開考試中報考n份試卷, 共付考試費$1090 ,計n
PUT E=1090
n = (1090-250)/120
n=7
參考: Me*
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