數學題目~...幫幫我解答,thx

2007-04-04 6:24 am
y隨a既立方而正變,且隨b而反變。如果a同b都增加20%,求y既百分變化
[請詳解/列式]

回答 (3)

2007-04-04 6:30 am
✔ 最佳答案
Let y = ka^3/b
Now,
a' = a(1+20%) = 1.2a
b' = b(1+20%) = 1.2b
y' = ka'^3/b'
= k(1.2a)^3/(1.2b)
= (1.2)^2 (ka^3/b)
= 1.44 y

% change in y = (y'-y)/y * 100%
= (1.44y-y)/y*100%
= 0.44*100%
=44% (increase)
2007-04-04 6:39 am
等我話比你知啦!!!!!!
就係咁嫁........

Let y = ka^3/b
Now,
a' = a(1+20%) = 1.2a
b' = b(1+20%) = 1.2b
y' = ka'^3/b'
= k(1.2a)^3/(1.2b)
= (1.2)^2 (ka^3/b)
= 1.44 y

% change in y = (y'-y)/y * 100%
= (1.44y-y)/y*100%
= 0.44*100%
=44% (increase)
2007-04-04 6:34 am
設y=ka^3/b,則a同b都增加20%時,有
y=k(1.2a)^3/1.2b
=ka^3*1.2^3/1.2b
=ka^3*1.2^2/b
=1.44(ka^3/b)
=ka^3/b+0.44(ka^3/b)
所以如果a同b都增加20%,y既百分變化44%


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