數學問題(急!!!)

2007-04-03 4:31 am
幫幫忙
解左下列關於y的方程
要列式
thx!!!!!
1.ax+5by=4c

2.3(7y+g)=5h-2y

3.m(2y-c)=10-y

4.2(t-y)=4s

5.m(5-2y)=m

6.
2y-a
---------=5
my

7.
g-y
------+k=10
h

回答 (4)

2007-04-03 4:38 am
✔ 最佳答案
1. ax+5by=4c
5by = 4c - ax
y = ( 4c-ax ) / 5b //
2. 3(7y+g)=5h-2y
21y + 3g = 5h - 2y
23y = 5h - 3g
y = ( 5h - 3g ) / 23 //
3. m(2y-c)=10-y
2my - mc = 10 - y
2my + y = mc + 10
y( 2m+1 ) = mc + 10
y = ( mc + 10 ) / ( 2m+1 ) //
4. 2(t-y)=4s
t -y = 2s
-y = 2s - t
y = -( 2s - t )
y = t - 2s //
6.
2y-a
---------=5
my
2y - a = 5my
2y - 5my = a
y( 2-5m ) = a
y = a / ( 2-5m )
7.
g-y
------+k=10
h
( g-y ) / h = 10 - k
g - y = 10h - hk
-y = 10h - hk - g
y = -10h + hk + g //

2007-04-02 20:47:48 補充:
sorry~漏左第五題~5.m(5-2y)=m5 - 2y = m/m5 - 2y = 1-2y = -4y = 2 //

2007-04-02 20:48:54 補充:
hx1077(新界312及313路線)計錯第七題!
參考: me~
2007-04-03 4:46 am
1.ax+5by=4c
5by=4c-ax
y=(4c-ax)/5b

2.3(7y+g)=5h-2y
19y+3g=5h
19y=5h-3g
y=5h-3g/19

3.m(2y-c)=10-y
2my-mc=10-y
2my+y=10+mc
(2m+1)y=10+mc
y=10+mc/2m+1

4.2(t-y)=4s
2t-2y=4s
t-y=2s
-y=2s-t
y=t-2s

5.m(5-2y)=m
5m-2my=m
-2my=-4m
2my=4m
y=2

6.2y-a/my=5
2y-a=5my
(5m-2)y=a
y=a/5m-2

7.(g-y/h)+k=10
g-y/h=10-k
g-y=(10-k)h
-y=(10-k)h-g
y=g-(10-k)h
參考: myself
2007-04-03 4:40 am
1. ax+5by=4c
5by=4c-ax
  4c-ax
y=---------
  5b
2. 3(7y+g)=5h-2y
21y+3g=5h-2y
21y+2y=5h-3g
23y=5h-3g
  5h-3g
y=--------
  23
3. m(2y-c)=10-y
2my-cm=10-y
2my-y=10-cm
y(2m-1)=10-cm
  10-cm
y=---------
  2m-1
4. 2(t-y)=4s
2t-2y=4s
-2y=4s-2t
  4s-2t
y=--------
   2
5. m(5-2y)=m
5m-2my=m
-2my=m-5m
-2my=-4m
  4
y=------
  2
6.
2y-a
---------=5
my
2y-a=5my
-a=5my-2y
-a=y(5m-2)
   a
y=--------
  5m-2
7.
g-y
------+k=10
h
g-y
------=10-k
h
g-y=h(10-k)
g-y=10h-hk
-y=10h-hk-g
y=-10h-hk-g
參考: 自己
2007-04-03 4:37 am
1.13
2.6
3.9
4.k
5.f
6.h
7.g
參考: me


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