✔ 最佳答案
1) B
Secondary voltage=110/55=2 V
Equivalent resistance of the bulbs=[(4^2/40)^2]/(4^2/40+4^2/40)=0.2 Ω
Current through the ammeter=2/0.2=10 A
Therefore option (2) is correct
Current in the primary coil=10/55=0.182 A
Therefore option (3) is incorrect
When (2) is correct and (3) is incorrect, the answer is B.
2) B
Images formed by concave lenses are always virtual, and therefore formed on the same side of the lens as the object. Options C and D are eliminated.
The incident ray from the bottom of the arrow should pass through the image arrow's bottom, therefore only B is correct.