differentiate the following function with respect to x.
y= (2x^2-1) / [(x-2)(x+3)]
form4 amaths
2007-03-28 5:33 am
回答 (1)
2007-03-28 5:48 am
✔ 最佳答案
y = ( 2x^2 - 1 ) / (x^2 + x - 6)用quotient rule
dy/dx
= [(x^2+x-6)(4x) - (2x^2-1)(2x+1)] / (x^2+x-6)^2
= [4x(x^2+x-6) - (4x^3+2x^2-2x-1)]/(x^2+x-6)^2
= (2x^2 - 22x +1) / [(x-2)(x-3)]^2
收錄日期: 2021-04-12 21:38:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070327000051KK04286