一塊質量為80g的泥膠從50cm的高處掉到一個電子秤上,泥膠和電子秤的相撞時間為0.08s
a 求泥膠在相撞前一刻的速度
力學問題~~~~~~~~help!!
2007-03-27 10:56 pm
回答 (2)
2007-03-28 3:10 am
✔ 最佳答案
By the law of conservation of energyLoss of potential energy = Gain of potential energy
mgh = 1/2 mv^2
gh = 1/2 v^2
(10)(50 X 0.01) = 1/2 v^2
v^2 = 10
v = 3.16 ms^-1
泥膠在相撞前一刻的速度為3.16 ms^-1.
參考: Myself~~~
收錄日期: 2021-04-25 19:52:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070327000051KK01772