1.化簡
√12+√75-√108
2.把(√3-√2)(2√2+√3)化成最簡形式
3. 把2/2√3-1有理化
help///數學題
2007-03-25 8:58 am
回答 (4)
2007-03-25 9:14 am
✔ 最佳答案
1.化簡√12+√75-√108
=√(22x3)+√(52x3)-√(62x3)
=2√3 + 5√3 - 6√3
= √3
2.把(√3-√2)(2√2+√3)化成最簡形式
(√3-√2)(2√2+√3)
= 2√6 + 3 – 4 – √6
= √6 - 1
3.把2/(2√3-1)有理化
2/(2√3-1)
= 2(2√3+1) / (2√3-1)(2√3+1)
= 2(2√3+1) / 11
2007-03-25 9:21 am
1.√12+√75-√108
= √(2x2x3) +√(5x5x3) -√(6x6x3)
= 2√3 + 5√3 - 6√3
=√3
2.(√3-√2)(2√2+√3)
= √3 (2√2+√3) - √2 (2√2+√3)
= 2√6 + 3 - 4 +√6
= 3√6 - 1
3.2 / (2√3-1)
= 2 (2√3 + 1) / [(2√3 - 1) (2√3 + 1)]
= 2 (2√3 + 1) / [(2√3)^2 - 1]
= 2 (2√3 + 1) / [12 - 1]
= 2 (2√3 + 1) / 11
= √(2x2x3) +√(5x5x3) -√(6x6x3)
= 2√3 + 5√3 - 6√3
=√3
2.(√3-√2)(2√2+√3)
= √3 (2√2+√3) - √2 (2√2+√3)
= 2√6 + 3 - 4 +√6
= 3√6 - 1
3.2 / (2√3-1)
= 2 (2√3 + 1) / [(2√3 - 1) (2√3 + 1)]
= 2 (2√3 + 1) / [(2√3)^2 - 1]
= 2 (2√3 + 1) / [12 - 1]
= 2 (2√3 + 1) / 11
2007-03-25 9:14 am
1.
√12+√75-√108
= √(2x2x3) +√(5x5x3) -√(6x6x3)
= 2√3 + 5√3 - 6√3
=√3
2.
(√3-√2)(2√2+√3)
= √3 (2√2+√3) - √2 (2√2+√3)
= 2√6 + 3 - 4 +√6
= 3√6 - 1
3.
2 / (2√3-1)
= 2 (2√3 + 1) / [(2√3 - 1) (2√3 + 1)]
= 2 (2√3 + 1) / [(2√3)^2 - 1]
= 2 (2√3 + 1) / [12 - 1]
= 2 (2√3 + 1) / 11
√12+√75-√108
= √(2x2x3) +√(5x5x3) -√(6x6x3)
= 2√3 + 5√3 - 6√3
=√3
2.
(√3-√2)(2√2+√3)
= √3 (2√2+√3) - √2 (2√2+√3)
= 2√6 + 3 - 4 +√6
= 3√6 - 1
3.
2 / (2√3-1)
= 2 (2√3 + 1) / [(2√3 - 1) (2√3 + 1)]
= 2 (2√3 + 1) / [(2√3)^2 - 1]
= 2 (2√3 + 1) / [12 - 1]
= 2 (2√3 + 1) / 11
2007-03-25 9:09 am
1.
√(3*4)+√(3*25)+√(3*36)
=2√3+5√3+6√3
=13√3
2.
2√6+3-4-√6
=√6-1
3.
2/2√3-1
=1/√3-1
=√3/3-1
=(√3-3)/3
√(3*4)+√(3*25)+√(3*36)
=2√3+5√3+6√3
=13√3
2.
2√6+3-4-√6
=√6-1
3.
2/2√3-1
=1/√3-1
=√3/3-1
=(√3-3)/3
收錄日期: 2021-04-12 18:49:23
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https://hk.answers.yahoo.com/question/index?qid=20070325000051KK00279