A.Maths
2007-03-24 8:45 am
Find, from first principles, the derivative of y = 1/(x+4) with respect to x.
回答 (2)
2007-03-24 9:45 am
參考: My Maths knowledge
2007-03-24 8:51 am
y = 1/(x+4)
y = (x+4)^(-1)
dy/dx = [(-1)(x+4)^(-2)](1)
dy/dx = -(x+4)^(-2)
dy/dx = 1/(x+4)^2
2007-03-24 00:54:43 補充：
The answer is -1/(x 4)^2... typo
2007-03-24 00:55:13 補充：
dy/dx = -1/(x 4)^2
y = (x+4)^(-1)
dy/dx = [(-1)(x+4)^(-2)](1)
dy/dx = -(x+4)^(-2)
dy/dx = 1/(x+4)^2
2007-03-24 00:54:43 補充：
The answer is -1/(x 4)^2... typo
2007-03-24 00:55:13 補充：
dy/dx = -1/(x 4)^2
參考: Me
收錄日期: 2021-04-16 16:51:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070324000051KK00162