數學問題..............
回答 (2)
2007-03-24 5:59 am
✔ 最佳答案
kx - 3y - 5 = 0, At y = 0,
kx - 5 = 0
x = 5/k
At x = 0
0 - 3y - 5 = 0
y = -5/3
Given: 三角形的面積是 25 平方單位,
而三角形的面積是: x * y /2 = 25
將 x 及 y 代入上式
=> 5/k * (-5/3)/2 = 25
=> k = - 1/10
2007-03-24 3:53 am
The straight L
when x=0
y=-5/3
wheny=0
kx-5=0
kx=5
x=5/k
1/2│[(0x(-5/3)+0x0+(5/k)x0)-(0x0+(5/k)x(-5/3)+0x0]│=25
│-25/3k│=50
-25/3k=50or-50
3k=75or-25
k=25ork=-25/3
when x=0
y=-5/3
wheny=0
kx-5=0
kx=5
x=5/k
1/2│[(0x(-5/3)+0x0+(5/k)x0)-(0x0+(5/k)x(-5/3)+0x0]│=25
│-25/3k│=50
-25/3k=50or-50
3k=75or-25
k=25ork=-25/3
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