Complex number i^2 = -1
2007-03-24 1:34 am
i^2 = -1 is a property of complex number, what are the values of i^1/3 and i^1/6?
回答 (1)
2007-03-24 1:49 am
✔ 最佳答案
i = cos90 + i sin90i^1/3
= [cos90 + i sin90]^1/3
= cos[(360k+90)/3] + i sin [360k+90)/3] where k = 0 to 2
i^1/6
= [cos90 + i sin90]^1/6
= cos[(360k+90)/6] + i sin [360k+90)/6] where k = 0 to 5
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https://hk.answers.yahoo.com/question/index?qid=20070323000051KK02324