分數!點計呢條
2-(-2)/3=?? <<-(3分之-2)
仲有2- 6/3=??
步驟plz
回答 (5)
2-(-2)/3=2+2/3=8/3
2- 6/3=2-2=0
2-(-2)/3
2-(-2)/3
=2+2/3
=8/3
2-6/3
=2-2
=0
參考: 自己
2-(-2)/3=2+2/3 因為負負得正
=6/3+2/3 通份母
=8/3
=2又3份2 假份數變帶份數
2- 6/3=6/3-6/3 通份母
=0
2-(-2)/3
=2+2/3
=2又2/3
=8/3,,
2- 6/3
=2-2
=0
參考: 自己
2-(-2)/3=2+2/3=8/3
2- 6/3=2-2=0
2007-03-22 22:38:51 補充:
2-(-2)/3
收錄日期: 2021-04-12 18:54:50
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