amathsss

2007-03-21 6:02 am
y = f(x) = x^2 , at x = 2

(1) sketch the graph

(2) does lim f(x) exist ?

step^^

回答 (2)

2007-03-21 3:55 pm
✔ 最佳答案
自己連埋o的綠色點啦, 小畫家好難畫~
y-axis 都冇mark 到
不過其實你對番xy值就畫到
手畫會易好多!

lim f(x) exists...
不過而家上堂冇時間, lunch先再答

2007-03-21 07:56:03 補充:
http://www.thedollpage.com/photopost/data/6044/1094abcsadjkljflhklhag.bmp唔記得貼圖 XD

2007-03-21 09:51:31 補充:
圖:X 0 1 2 3 4 5Y 0 1 4 9 16 25lim f(x) x=?今日冇amaths堂我冇notes...印象中係問某個value的...今晚先答!

2007-03-21 17:58:13 補充:
x冇指明係咩o既我唔知點prove啊...假設x=2啦lim f(x) = 4 x→2-f(2) = 4∵lim f(x) = 4 = f(2) x→2∴ lim f(x) exist
參考: myself
2007-03-21 6:09 am
y = f(x) = x^2 , at x = 2

(1) sketch the graph
i am sorry that i can't stetch the graph.
tips:
y = f(x) = x^2
when x = 0,y = 0,so it passes through (0,0)
and it is increasing with an increasing slope when x > 0 and x < 0
its vertex exist at(0,0)

(2) does lim f(x) exist ?
since there is a continueous function
there is limit of f(x) existing



2007-03-20 22:17:27 補充:
at x = 2 fory = f(x) = x^2y = lim{x- 2} x^2y = 2^2y = 4
參考: em


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