The formula for hydrated iron(II) sulphate is FeSO4．xH2O.On strong heating, 20.1g of the sulphate produces 9.1g of water.What is the value of x?
(Relative atomic masses: H=1 O=16 S=32.1 Fe=56)
Reacting mass
2007-03-21 3:22 am
回答 (1)
2007-03-21 4:17 am
✔ 最佳答案
FeSO4．xH2O → FeSO4 + xH2Ono. of mole of FeSO4．xH2O used = 20.1/(56+32.1+16*4+x(2+16))=20.1/(152.1+18x)
no. of mole of H2O produced = 9.1/(2+16) = 9.1/18
from the equation, mole ratio of FeSO4．xH2O : H2O = 1 : x
so (20.1/(152.1+18x))/(9.1/18) = 1/x
x = 6.99 (3 sig. fig.)
= 7
so x = 7
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