How to factorise :
x^3 -3x^2 -1597x +1599 = 0
Factorization
2007-03-20 1:13 am
回答 (2)
2007-03-20 1:22 am
✔ 最佳答案
Let F(x) = x^3 -3x^2 -1597x +1599 F(1) = 1^3 - 3(1)^2 - 1597 (1) + 1599
= 0
Therefore x-1 is a factor of F(x).
By Long division,
F(x) = (x-1)(x^2 - 2x - 1599)
Hence x^3 -3x^2 -1597x +1599 = (x-1)(x^2 - 2x - 1599) = 0
參考: My Maths Knowledge
2007-03-20 1:44 am
Let F(x) = x^3 -3x^2 -1597x +1599
F(1) = 1^3 - 3(1)^2 - 1597 (1) + 1599
= 0
Therefore x-1 is a factor of F(x).
By Long division,
F(x) = (x-1)(x^2 - 2x - 1599)
Hence x^3 -3x^2 -1597x +1599 = (x-1)(x^2 - 2x - 1599) = 0
按 chocolate328154 的回答
(x^2 - 2x - 1599) = (x+39)(x-41)
所以
x^3 -3x^2 -1597x +1599 = (x-1)(x+39)(x-41) = 0
F(1) = 1^3 - 3(1)^2 - 1597 (1) + 1599
= 0
Therefore x-1 is a factor of F(x).
By Long division,
F(x) = (x-1)(x^2 - 2x - 1599)
Hence x^3 -3x^2 -1597x +1599 = (x-1)(x^2 - 2x - 1599) = 0
按 chocolate328154 的回答
(x^2 - 2x - 1599) = (x+39)(x-41)
所以
x^3 -3x^2 -1597x +1599 = (x-1)(x+39)(x-41) = 0
收錄日期: 2021-04-13 16:52:40
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