我想問關於數學代數的問題(急!!!最佳有30points)

(1)
(X - 4)(X) + (2X - 1) = X^2 - (4 - X)
X^2 - 4X + 2X - 1 = X^2 - 4 + X
-2X - 1 = -4 + X
3 = 3X
X = 1

(2)
2(2X + 1)(X) = 3X^2 + (X)(X - 1)
4X^2 + 2X = 3X^2 + X^2 - X
3X = 0
X = 0

1.解：依題意得：

(x^2-4x)+2x-1=x^2-4+x

-4x+2x-x=-4+1

-3x=-3

x=1

2.解：依題意得：

4x^2+2x=3x^2+x^2-x

3x=0

x=0