Use equations to explain the observation
1.when a few drops of copper(II) sulphate solution are added to the reagent in bottles dliute sodium hydroxide solution or duilte sulphuric acid, a pale blue precipitate forms.
2. When carbon dioxide is pass through the reagent in dilute sulphuric acid, a white precipitate forms.
THX~
Chem `
2007-03-18 1:04 am
回答 (2)
2007-03-19 9:36 am
✔ 最佳答案
1. When copper(II) sulphate solution is added to sodium hydroxide solution, a blue precipitate is formed.Cu^2+(aq) + 2OH^-(aq) → Cu(OH)2(s)
When copper(II) sulphate solution is added to dilute sulphuric acid, there is NO REACTION.
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2. When carbon dioxide is passed through dilute sulphuric acid, ther is NO REACTION.
2007-03-19 01:38:02 補充：
產生藍色沉澱的 full equation :CuSO4(aq) 2NaOH(aq) → Cu(OH)2(s) Na2SO4(aq)
2007-03-19 01:40:07 補充：
唔好人地話有反應，你就作條 equation。HCO3 根本就冇呢樣野，SO3 遇水有劇烈反應，亂作 equation。
2007-03-18 8:32 am
1.
CuSO4+ 2NaOH ---> Cu(OH)2(s)+ Na2SO4
2.
2CO2+ 2H2SO4(aq.) ---> 2HCO3 + 2SO3
CuSO4+ 2NaOH ---> Cu(OH)2(s)+ Na2SO4
2.
2CO2+ 2H2SO4(aq.) ---> 2HCO3 + 2SO3
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